0=16x^2-56x+49

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Solution for 0=16x^2-56x+49 equation: 



0=16x^2-56x+49

We move all terms to the left:

0-(16x^2-56x+49)=0

We add all the numbers together, and all the variables

-(16x^2-56x+49)=0

We get rid of parentheses

-16x^2+56x-49=0

a = -16; b = 56; c = -49;
Δ = b2-4ac
Δ = 562-4·(-16)·(-49)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-56}{-32}=1+3/4$

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